Cálculo Integral

	∫abf(x)${\displaystyle {\int }_b^{a}f\left(x\right)}$ dx=−∫baf(x)${\displaystyle dx=-{\int }_a^{b}f\left(x\right)}$ dx${\displaystyle dx}$
	∫aaf(x)${\displaystyle {\int }_a^{a}f\left(x\right)}$ dx=0${\displaystyle dx=0}$
	∫baf(x)${\displaystyle {\int }_a^{b}f\left(x\right)}$ dx=∫caf(x)${\displaystyle dx={\int }_a^{c}f\left(x\right)}$ dx+∫bcf(x)${\displaystyle dx+{\int }_c^{b}f\left(x\right)}$ dx${\displaystyle dx}$
	∫ba(f(x)+g(x))${\displaystyle {\int }_a^b(f\left(x\right)+g\left(x\right))}$ dx=∫baf(x)${\displaystyle dx={\int }_a^{b}f\left(x\right)}$ dx+∫bag(x)${\displaystyle dx+{\int }_a^{b}g\left(x\right)}$ dx${\displaystyle dx}$
	∫bak.f(x)${\displaystyle {\int }_a^{b}k.f\left(x\right)}$ dx=k∫baf(x)${\displaystyle dx=k{\int }_a^{b}f\left(x\right)}$ dx${\displaystyle dx}$
	∫baf(x)${\displaystyle {\int }_a^{b}f\left(x\right)}$ dx=F(b)−F(a)${\displaystyle dx=F\left(b\right)-F\left(a\right)}$, onde F${\displaystyle F}$ é primitiva de f${\displaystyle f}$ no intervalo [a,b]