Conjuntos e Probabilidades

	nA′p=np${\displaystyle {}^n{A}_p^{\prime }=n^p}$	ex : 5A′3=53=125${\displaystyle {}^5{A}_3^{\prime }=5^3=125}$
	nCp=nApp!=n!(n−p)!×p!${\displaystyle {}^n{C}_p=\frac{{}^n{A}_p}{p!}=\frac{n!}{(n-p)!\times p!}}$	ex : 5C4=5A44!=5${\displaystyle {}^5{C}_4=\frac{{}^5{A}_4}{4!}=5}$
	Valor Médio	μ=x1p1+x2p2+...+xkpk${\displaystyle \mu =x_1{p}_1+x_2{p}_2+...+x_k{p}_k}$
	Desvio Padrão	σ=∑i=1kpi(xi−μ)2−−−−−−−−−−−−⎷${\displaystyle \sigma =\sqrt{\sum _{i=1}^k{p}_i{(x_i-\mu )}^2}}$
	P(X=k)=nCk.pk.(1−p)n−k${\displaystyle P(X=k)={}^n{C}_k.p^k.{(1-p)}^{n-k}}$	ex : B(10;0,6)${\displaystyle B(10;0,6)}$ P(X=3)=10C3×0,63×0,47